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(D) The maximum frequency $(f_{max})$ of $X$-rays produced is given by the relation $hf_{max} = eV$,where $V$ is the accelerating potential.$f_{max} =

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$14 	imes 10^{18} \,Hz$

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(D) The maximum frequency $(f_{max})$ of $X$-rays produced is given by the relation $hf_{max} = eV$,where $V$ is the accelerating potential.$f_{max} = \frac{eV}{h} = \frac{1.6 	imes 10^{-19} \,C 	imes 50 	imes 10^3 \,V}{6.63 	imes 10^{-34} \,J \cdot s}$$f_{max} \approx 1.206 	imes 10^{19} \,Hz = 12.06 	imes 10^{18} \,Hz$.Since the maximum frequency possible is approximately $12.06 	imes 10^{18} \,Hz$,any frequency higher than this cannot be obtained.Therefore,$14 	imes 10^{18} \,Hz$ is not possible.

An electron beam strikes a target at an accelerating potential of $50 \,kV$. Which of the following frequencies of $X$-rays will not be obtained?

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