Surfaces A and B are at the same potential V' | vedclass

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(A) The work done $W$ in moving a charge $q$ from a point $A$ to a point $B$ in an electric field is given by the formula:$W = q(V_B - V_A)$where $V_A

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) The work done $W$ in moving a charge $q$ from a point $A$ to a point $B$ in an electric field is given by the formula:$W = q(V_B - V_A)$where $V_A$ and $V_B$ are the electric potentials at points $A$ and $B$ respectively.Given that both surfaces $A$ and $B$ are at the same potential $V'$,we have $V_A = V_B = V'$.Substituting these values into the formula:$W = q(V' - V') = q(0) = 0$Therefore,the work done in moving the charge from $A$ to $B$ is $0$.

Surfaces $A$ and $B$ are at the same potential $V'$. The work done in moving a charge $q$ from $A$ to $B$ is ........

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