Two point charges of +2 , mu text{C} and +6 , | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Coulomb's Law,the force between two charges is given by $F = \frac{k q_1 q_2}{r^2}$.Initially,$q_1 = 2 \, \mu 	ext{C}$ and $q_2 = 6

Vedclass · Accepted Answer

$4 \, 	ext{N}$ (attractive)

Vedclass · Answer

(A) According to Coulomb's Law,the force between two charges is given by $F = \frac{k q_1 q_2}{r^2}$.Initially,$q_1 = 2 \, \mu 	ext{C}$ and $q_2 = 6 \, \mu 	ext{C}$,and $F = 12 \, 	ext{N}$.So,$12 = \frac{k (2 	imes 10^{-6}) (6 	imes 10^{-6})}{r^2} \implies \frac{k}{r^2} = \frac{12}{12 	imes 10^{-12}} = 10^{12} \, 	ext{N} \cdot 	ext{m}^2/	ext{C}^2$.After adding $-4 \, \mu 	ext{C}$ to each charge:$q_1' = 2 - 4 = -2 \, \mu 	ext{C}$$q_2' = 6 - 4 = +2 \, \mu 	ext{C}$The new force $F'$ is $F' = \frac{k q_1' q_2'}{r^2} = \frac{k (-2 	imes 10^{-6}) (2 	imes 10^{-6})}{r^2}$.Substituting $\frac{k}{r^2} = 10^{12}$,we get $F' = 10^{12} 	imes (-4 	imes 10^{-12}) = -4 \, 	ext{N}$.The negative sign indicates that the force is attractive. Thus,the magnitude is $4 \, 	ext{N}$ and the nature is attractive.

Two point charges of $+2 \, \mu \text{C}$ and $+6 \, \mu \text{C}$ repel each other with a force of $12 \, \text{N}$. If a charge of $-4 \, \mu \text{C}$ is added to each,the force will be:

Similar Questions

State the principle of superposition for electric forces.

$A$ proton and an anti-proton come close to each other in vacuum such that the distance between them is $10 \, cm$. Consider the potential energy to be zero at infinity. The velocity at this distance will be ........... $\, m/s$.

Two electric charges $+q$ and $+q$ are placed at a distance $r$. The force between them is $F$. If one charge is fixed and the other moves in a circle of radius $r$,the work done will be .......

Three point charges $+q$,$+2q$,and $+4q$ are placed along a straight line such that the charge $+2q$ is equidistant from the other two charges. The ratio of the net electrostatic force on charges $+q$ and $+4q$ is

Two charges $2 C$ and $6 C$ are separated by a finite distance. If a charge of $-4 C$ is added to each of them, the initial force of $12 \times 10^3 \,N$ will change to

Vedclass Test Series

Exam Paper Generator

Online Exam Module