A parallel plate capacitor is connected to a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The potential difference $V$ across the plates remains constant because the capacitor is connected to a battery.The electric field $E$ between the

Vedclass · Accepted Answer

decreases and the charge on the plates also decreases.

Vedclass · Answer

(A) The potential difference $V$ across the plates remains constant because the capacitor is connected to a battery.The electric field $E$ between the plates is given by $E = V/d$,where $d$ is the distance between the plates.As the plates are moved further apart,$d$ increases,so $E = V/d$ decreases.The capacitance $C$ of a parallel plate capacitor is given by $C = \epsilon_0 A / d$.As $d$ increases,the capacitance $C$ decreases.The charge $Q$ on the plates is given by $Q = CV$.Since $C$ decreases and $V$ is constant,the charge $Q$ on the plates also decreases.Therefore,both the electric field intensity and the charge on the plates decrease.

$A$ parallel plate capacitor is connected to a battery,which maintains a constant potential difference. If the plates of the capacitor are moved further apart,the electric field intensity...

Similar Questions

In an isolated parallel plate capacitor of capacitance $C$,the four surfaces have charges $Q_1$,$Q_2$,$Q_3$,and $Q_4$ as shown. The potential difference between the plates is

If the distance between the plates of a parallel plate capacitor of capacity $10 \mu F$ is doubled,then the new capacity will be: (in $\mu F$)

Two identical thin metal plates have charges $q_{1}$ and $q_{2}$ respectively,such that $q_{1} > q_{2}$. The plates are brought close to each other to form a parallel plate capacitor of capacitance $C$. The potential difference between them is:

The force between the plates of a parallel plate capacitor of capacitance $C$ and distance of separation of the plates $d$ with a potential difference $V$ between the plates is

Three plates $A, B$ and $C$ each of area $0.1 \ m^2$ are separated by $0.885 \ mm$ from each other as shown in the figure. A $10 \ V$ battery is used to charge the system. The energy stored in the system is

Vedclass Test Series

Exam Paper Generator

Online Exam Module