Two small balls,each having a negative charge | vedclass

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(A) In a satellite,the condition is one of weightlessness,meaning the effective gravitational force $mg = 0$.Due to the electrostatic force of repulsi

Vedclass · Accepted Answer

$180^{\circ}, \frac{kQ^2}{4L^2}$

Vedclass · Answer

(A) In a satellite,the condition is one of weightlessness,meaning the effective gravitational force $mg = 0$.Due to the electrostatic force of repulsion between the two identical negative charges $Q$,the balls will push each other away until the strings are fully extended in opposite directions.Since the strings are of length $L$,the distance between the two balls becomes $2L$.The angle between the two strings is $180^{\circ}$.The tension $T$ in each string is balanced by the electrostatic force of repulsion $F_e$ between the two charges.Using Coulomb's Law: $F_e = \frac{k |Q_1 Q_2|}{r^2} = \frac{k Q^2}{(2L)^2} = \frac{k Q^2}{4L^2}$.Therefore,the tension $T = F_e = \frac{k Q^2}{4L^2} 	ext{ N}$.

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