Three capacitors,each of value 1 mutext{F},a | vedclass

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(D) Let the capacitance of each capacitor be $C = 1 \ \mu	ext{F}$.If two capacitors are connected in series,their equivalent capacitance is $C_s = \f

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The third capacitor is connected in parallel with the series combination of the other two.

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(D) Let the capacitance of each capacitor be $C = 1 \ \mu	ext{F}$.If two capacitors are connected in series,their equivalent capacitance is $C_s = \frac{C 	imes C}{C + C} = \frac{C}{2} = 0.5 \ \mu	ext{F}$.If this combination is connected in parallel with the third capacitor,the total equivalent capacitance is $C_{	ext{eff}} = C_s + C = 0.5 \ \mu	ext{F} + 1 \ \mu	ext{F} = 1.5 \ \mu	ext{F}$.Therefore,the third capacitor is connected in parallel with the series combination of the other two capacitors.

Three capacitors,each of value $1 \ \mu\text{F}$,are connected in such a way that the resultant capacitance is $1.5 \ \mu\text{F}$. Then:

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