The dielectric constant of pure water is 81. | vedclass

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Question

(A) The permittivity of a medium is given by the formula $\epsilon = \epsilon_0 \epsilon_r$,where $\epsilon_0$ is the permittivity of free space $(8.8

Vedclass · Accepted Answer

$7.16 	imes 10^{-10} 	ext{ MKS units}$

Vedclass · Answer

(A) The permittivity of a medium is given by the formula $\epsilon = \epsilon_0 \epsilon_r$,where $\epsilon_0$ is the permittivity of free space $(8.854 	imes 10^{-12} 	ext{ C}^2/	ext{N} \cdot 	ext{m}^2)$ and $\epsilon_r$ is the dielectric constant.Given $\epsilon_r = 81$.Therefore,$\epsilon = (8.854 	imes 10^{-12}) 	imes 81$.$\epsilon \approx 7.17 	imes 10^{-10} 	ext{ C}^2/	ext{N} \cdot 	ext{m}^2$ (or $MKS$ units).Thus,the correct option is $A$.

The dielectric constant of pure water is $81$. Its permittivity will be ........

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