A capacitor of 6 mu F is charged from 10 V | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The energy stored in a capacitor is given by $E = \frac{1}{2} C V^2$.The increase in energy is given by $\Delta E = E_{final} - E_{initial} = \fra

Vedclass · Accepted Answer

$9 	imes 10^{-4} \ J$

Vedclass · Answer

(B) The energy stored in a capacitor is given by $E = \frac{1}{2} C V^2$.The increase in energy is given by $\Delta E = E_{final} - E_{initial} = \frac{1}{2} C (V_{final}^2 - V_{initial}^2)$.Given: $C = 6 \ \mu F = 6 	imes 10^{-6} \ F$,$V_{initial} = 10 \ V$,and $V_{final} = 20 \ V$.Substituting the values:$\Delta E = \frac{1}{2} 	imes (6 	imes 10^{-6}) 	imes (20^2 - 10^2)$$\Delta E = 3 	imes 10^{-6} 	imes (400 - 100)$$\Delta E = 3 	imes 10^{-6} 	imes 300$$\Delta E = 900 	imes 10^{-6} \ J = 9 	imes 10^{-4} \ J$.

$A$ capacitor of $6 \ \mu F$ is charged from $10 \ V$ to $20 \ V$. The increase in its stored energy is:

Similar Questions

The energy stored in a capacitor is $W$. To double the charge on the plates of the capacitor,the additional work to be done is

If the charge on the capacitor is increased by $3 \ C$,the energy stored in it increases by $21 \%$. The original charge on the capacitor is (in $C$)

$A$ parallel plate capacitor has a uniform electric field $E$ in the space between the plates. If the distance between the plates is $d$ and the area of each plate is $A,$ the energy stored in the capacitor is

The energy stored in a capacitor of capacitance $C$ charged to a potential $V$ is:

$A$ $5.0 \mu F$ capacitor is charged to a potential difference of $800 V$ and discharged through a conductor. The energy (in $J$) given to the conductor during the discharge is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module