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(C) The two spheres are each charged with $+q$ and are separated by a distance $r = 2a$.According to Coulomb's Law,the electrostatic repulsive force $

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$\frac{q^2}{16\pi \varepsilon_0 a^2}$

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(C) The two spheres are each charged with $+q$ and are separated by a distance $r = 2a$.According to Coulomb's Law,the electrostatic repulsive force $F$ between the two charges is given by:$F = \frac{1}{4\pi \varepsilon_0} \cdot \frac{q_1 q_2}{r^2}$Substituting the given values $q_1 = q$,$q_2 = q$,and $r = 2a$:$F = \frac{1}{4\pi \varepsilon_0} \cdot \frac{q \cdot q}{(2a)^2}$$F = \frac{1}{4\pi \varepsilon_0} \cdot \frac{q^2}{4a^2}$$F = \frac{q^2}{16\pi \varepsilon_0 a^2}$Since the spheres are in equilibrium,the tension $T$ in the string must balance the electrostatic repulsive force.Therefore,$T = F = \frac{q^2}{16\pi \varepsilon_0 a^2}$.

Two small spheres,each carrying a charge of $+q$,are connected by an insulating string of length $2a$. What is the tension in the string?

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