Two points P and Q are at potentials of 10 V | vedclass

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(B) The work done $W$ in moving a charge $q$ from point $P$ to point $Q$ is given by $W = q(V_Q - V_P)$.Here,the charge $q$ is the total charge of $10

Vedclass · Accepted Answer

$2.24 	imes 10^{-16} \ J$

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(B) The work done $W$ in moving a charge $q$ from point $P$ to point $Q$ is given by $W = q(V_Q - V_P)$.Here,the charge $q$ is the total charge of $100$ electrons,so $q = -100e = -100 	imes 1.6 	imes 10^{-19} \ C = -1.6 	imes 10^{-17} \ C$.The potential difference is $V_Q - V_P = (-4 \ V) - (10 \ V) = -14 \ V$.Substituting these values into the work formula:$W = (-1.6 	imes 10^{-17} \ C) 	imes (-14 \ V) = 22.4 	imes 10^{-17} \ J = 2.24 	imes 10^{-16} \ J$.

Two points $P$ and $Q$ are at potentials of $10 \ V$ and $-4 \ V$ respectively. The work done in moving $100$ electrons from $P$ to $Q$ is .....

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