(C) Initial charge on the $6\ \mu F$ capacitor is $Q = C_1 V_0 = 6\ \mu F \times 100\, V = 600\ \mu C$.When connected in parallel,both capacitors reac

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(C) Initial charge on the $6\ \mu F$ capacitor is $Q = C_1 V_0 = 6\ \mu F \times 100\, V = 600\ \mu C$.When connected in parallel,both capacitors reach a common potential $V$.The charge on the capacitors will be $q_1 = C_1 V$ and $q_2 = C_2 V$.The ratio of charges is $\frac{q_1}{q_2} = \frac{C_1 V}{C_2 V} = \frac{C_1}{C_2} = \frac{6}{14}$.By conservation of charge,$q_1 + q_2 = Q = 600\ \mu C$.$C_1 V + C_2 V = 600\ \mu C \Rightarrow V(6 + 14) = 600$.$V = \frac{600}{20} = 30\, V$.Thus,the ratio is $6/14$ and the potential is $30\, V$.

Class 12 Physics Electric Potential and Capacitance Sharing of Charge in Capacitor Circuit

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$A$ capacitor of capacitance $6\ \mu F$ is charged to $100\, V$. It is then connected to another uncharged capacitor of capacitance $14\ \mu F$. Find the ratio of charges on the $6\ \mu F$ and $14\ \mu F$ capacitors and the potential across the $6\ \mu F$ capacitor.

A
$6/14$ and $50\, V$
B
$14/6$ and $30\, V$
C
$6/14$ and $30\, V$
D
$14/6$ and $0\, V$

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Electric Potential and Capacitance

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Sharing of Charge in Capacitor Circuit

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$A$ capacitor of capacitance $6\ \mu F$ is charged to $100\, V$. It is then connected to another uncharged capacitor of capacitance $14\ \mu F$. Find the ratio of charges on the $6\ \mu F$ and $14\ \mu F$ capacitors and the potential across the $6\ \mu F$ capacitor.

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$A$ $4 \mu F$ capacitor is charged by a $200 \ V$ battery. It is then disconnected from the supply and connected to another uncharged $2 \mu F$ capacitor. During the process,the loss of energy (in $J$) is:

Two metallic charged spheres whose radii are $20\,cm$ and $10\,cm$ respectively,have each $150\,\mu C$ positive charge. The common potential after they are connected by a conducting wire is

$A$ $10 \mu F$ capacitor is charged by a $100 V$ battery. It is disconnected from the battery and is connected to another uncharged capacitor of capacitance $30 \mu F$. During this process,the electrostatic energy lost by the first capacitor is

Two spheres of radii $1 \, cm$ and $2 \, cm$ are charged with $1.5 \times 10^{-8} \, C$ and $0.3 \times 10^{-7} \, C$ of positive charge,respectively. When they are connected by a wire,the charge will flow:

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