Three point charges +q, -2q and +q are placed | vedclass

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(A) The system consists of a charge $-2q$ at the origin $(0,0,0)$,a charge $+q$ at $(0,a,0)$,and a charge $+q$ at $(a,0,0)$.We can treat this as two d

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Magnitude $\sqrt{2}qa$ in the direction of the line joining $(0, 0, 0)$ and $(a, a, 0)$

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(A) The system consists of a charge $-2q$ at the origin $(0,0,0)$,a charge $+q$ at $(0,a,0)$,and a charge $+q$ at $(a,0,0)$.We can treat this as two dipoles: $\vec{p}_1$ formed by $-q$ at the origin and $+q$ at $(a,0,0)$,and $\vec{p}_2$ formed by $-q$ at the origin and $+q$ at $(0,a,0)$.$\vec{p}_1 = q(a\hat{i} - 0\hat{i}) = qa\hat{i}$.$\vec{p}_2 = q(a\hat{j} - 0\hat{j}) = qa\hat{j}$.The total dipole moment is $\vec{p} = \vec{p}_1 + \vec{p}_2 = qa\hat{i} + qa\hat{j}$.The magnitude is $|\vec{p}| = \sqrt{(qa)^2 + (qa)^2} = \sqrt{2}qa$.The direction is given by the vector $\hat{i} + \hat{j}$,which is along the line joining $(0,0,0)$ and $(a,a,0)$.

Three point charges $+q, -2q$ and $+q$ are placed at points $(x = 0, y = a, z = 0)$,$(x = 0, y = 0, z = 0)$ and $(x = a, y = 0, z = 0)$ respectively. The magnitude and direction of the electric dipole moment vector of this system are:

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