Two capacitors of $1 \ \mu F$ and $2 \ \mu F$ are connected in series. This combination is charged to a potential difference of $120 \ V$. What is the potential difference across the $1 \ \mu F$ capacitor in volts?

Two capacitors each having a capacitance $2 \times 10^{-6} \ F$ and a breakdown voltage $5000 \ V$,are joined in series. What will be the resultant capacitance and the breakdown voltage of the combination?

An infinite number of identical capacitors,each with a capacitance of $1 \ \mu F$,are connected as shown in the figure. Find the equivalent capacitance between $A$ and $B$ in $\mu F$.

To obtain $3\,\mu F$ capacitance from three capacitors of $2\,\mu F$ each,they will be arranged as:

The combination of capacitors with $C_1 = 3\,\mu F$,$C_2 = 4\,\mu F$,and $C_3 = 2\,\mu F$ is charged by connecting $A$ and $B$ to a battery. Consider the following statements:
$I.$ Energy stored in $C_1$ $=$ Energy stored in $C_2$ $+$ Energy stored in $C_3$
$II.$ Charge on $C_1$ $=$ Charge on $C_2$ $+$ Charge on $C_3$
$III.$ Potential drop across $C_1$ $=$ Potential drop across $C_2$ $=$ Potential drop across $C_3$
Which of these is/are correct?

Find the equivalent capacitance between the points $A$ and $B$ in the given figure.