Two balls with charges +7 mu C and -5 mu C | vedclass

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(A) Initially,the charges are $q_1 = +7 \ \mu C$ and $q_2 = -5 \ \mu C$. The force between them is given by Coulomb's Law: $F = k \frac{|q_1 q_2|}{r^2

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$F$

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(A) Initially,the charges are $q_1 = +7 \ \mu C$ and $q_2 = -5 \ \mu C$. The force between them is given by Coulomb's Law: $F = k \frac{|q_1 q_2|}{r^2} = k \frac{|(7 	imes 10^{-6})(-5 	imes 10^{-6})|}{r^2} = k \frac{35 	imes 10^{-12}}{r^2}$.After adding $-2 \ \mu C$ to both,the new charges are:$q_1' = 7 \ \mu C - 2 \ \mu C = +5 \ \mu C$$q_2' = -5 \ \mu C - 2 \ \mu C = -7 \ \mu C$.The new force $F'$ is:$F' = k \frac{|q_1' q_2'|}{r^2} = k \frac{|(5 	imes 10^{-6})(-7 	imes 10^{-6})|}{r^2} = k \frac{35 	imes 10^{-12}}{r^2}$.Comparing the two expressions,we see that $F' = F$.

Two balls with charges $+7 \ \mu C$ and $-5 \ \mu C$ attract each other with a force $F$. If $-2 \ \mu C$ charge is added to both,what will be the force between them?

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