The work done in placing a charge of 8 times | vedclass

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(D) The energy stored in a capacitor,which represents the work done to charge it,is given by the formula: $W = \frac{Q^2}{2C}$.Given:Charge $Q = 8 	i

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$32 	imes 10^{-32} \ J$

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(D) The energy stored in a capacitor,which represents the work done to charge it,is given by the formula: $W = \frac{Q^2}{2C}$.Given:Charge $Q = 8 	imes 10^{-18} \ C$Capacitance $C = 100 \ \mu F = 100 	imes 10^{-6} \ F = 10^{-4} \ F$.Substituting the values into the formula:$W = \frac{(8 	imes 10^{-18})^2}{2 	imes 10^{-4}}$$W = \frac{64 	imes 10^{-36}}{2 	imes 10^{-4}}$$W = 32 	imes 10^{-32} \ J$.Thus,the work done is $32 	imes 10^{-32} \ J$.

The work done in placing a charge of $8 \times 10^{-18} \ C$ on a capacitor of capacitance $100 \ \mu F$ is:

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