The radius of a nucleus with atomic number Z | vedclass

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(B) The electric potential $V$ at the surface of a nucleus is given by the formula $V = \frac{1}{4\pi\epsilon_0} \frac{q}{R}$.Here,the charge of the n

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$80 \ kV$

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(B) The electric potential $V$ at the surface of a nucleus is given by the formula $V = \frac{1}{4\pi\epsilon_0} \frac{q}{R}$.Here,the charge of the nucleus is $q = Ze$,where $Z = 50$ and $e = 1.6 	imes 10^{-19} \ C$.The radius $R = 9 	imes 10^{-13} \ m$.The constant $\frac{1}{4\pi\epsilon_0} = 9 	imes 10^9 \ N \ m^2/C^2$.Substituting the values:$V = (9 	imes 10^9) 	imes \frac{50 	imes 1.6 	imes 10^{-19}}{9 	imes 10^{-13}}$$V = (9 	imes 10^9) 	imes \frac{80 	imes 10^{-19}}{9 	imes 10^{-13}}$$V = 80 	imes 10^{9 - 19 + 13} \ V$$V = 80 	imes 10^3 \ V = 80 \ kV$.

The radius of a nucleus with atomic number $Z = 50$ is $9 \times 10^{-13} \ m$. The electric potential at its surface is:

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