The XOR gate gives an output of 1 only when t | vedclass

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(B) The $XOR$ (Exclusive $OR$) gate is a digital logic gate that implements exclusive disjunction. Its Boolean expression is $Y = A \oplus B$,which is

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(B) The $XOR$ (Exclusive $OR$) gate is a digital logic gate that implements exclusive disjunction. Its Boolean expression is $Y = A \oplus B$,which is equivalent to $Y = A\bar{B} + \bar{A}B$. The truth table for a two-input $XOR$ gate is: If $A=0, B=0$,then $Y=0$. If $A=0, B=1$,then $Y=1$. If $A=1, B=0$,then $Y=1$. If $A=1, B=1$,then $Y=0$. From the truth table,it is clear that the output is $1$ (High) only when the inputs $A$ and $B$ are different.

The $XOR$ gate gives an output of $1$ only when the two inputs are . . . . .

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