The correct relationship between $\alpha$ and $\beta$ for a transistor is ........

$A$ transistor is used in an amplifier circuit in common emitter mode. If the base current changes by $100 \,\mu A$, it brings a change of $10 \,mA$ in collector current. If the load resistance is $2 \,k \Omega$ and input resistance is $1 \,k \Omega$, the value of power gain is $x \times 10^{4}$. The value of $x$ is . . . . . . .

In a common emitter transistor amplifier, the output resistance is $500 \text{ k}\Omega$ and the current gain $\beta = 50$. If the power gain of the amplifier is $5 \times 10^6$, what is the input resistance (in $\Omega$)?

$A$ common emitter amplifier circuit is shown in the figure. For the transistor used in the circuit,the current amplification factor is $\beta_{dc} = 100$. Other parameters are given in the figure.

Assertion: In a transistor,the base is made thin.
Reason: $A$ thin base makes the transistor stable.

In an amplifier circuit,the value of the load resistance $R_L$ is $2 \text{ k}\Omega$. $A$ change of $10 \text{ }\mu\text{A}$ in the base current of the transistor results in a change of $1 \text{ mA}$ in the collector current. The change in the collector-emitter voltage $(V_{CE})$ is ....... $V$.