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(D) To identify the logic gate,we analyze the truth table from the given waveforms:
$1$. At the start,$A=0, B=0$,and the output $C=0$.
$2$. Next,$A=

Vedclass · Accepted Answer

$XOR$ gate

Vedclass · Answer

(D) To identify the logic gate,we analyze the truth table from the given waveforms:
$1$. At the start,$A=0, B=0$,and the output $C=0$.
$2$. Next,$A=1, B=0$,and the output $C=1$.
$3$. Then,$A=1, B=1$,and the output $C=0$.
$4$. Finally,$A=0, B=1$,and the output $C=1$.
Summarizing the truth table:

	
		
			$A$
			$B$
			$C$
		
		
			$0$
			$0$
			$0$
		
		
			$1$
			$0$
			$1$
		
		
			$1$
			$1$
			$0$
		
		
			$0$
			$1$
			$1$
		
	


Comparing this with standard logic gates:
- For an $OR$ gate,$C = A + B$. Here,$1+1=1$,but the output is $0$. So,it is not $OR$.
- For an $AND$ gate,$C = A \cdot B$. Here,$1 \cdot 0 = 0$,but the output is $1$. So,it is not $AND$.
- For a $NOR$ gate,$C = \overline{A+B}$. Here,$0+0=1$,but the output is $0$. So,it is not $NOR$.
- For an $XOR$ gate,$C = A \oplus B$. The truth table matches the $XOR$ gate,as the output is $1$ only when the inputs are different.
Therefore,the correct logic gate is the $XOR$ gate.

In the given figure,$A$ and $B$ are inputs and $C$ is the output of a logic gate circuit. The voltage waveforms of $A$,$B$,and $C$ are shown in the figure. Identify the logic gate.

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