$A$ transistor is connected in a common emitter configuration with $R_o = 4 \text{ k}\Omega$,$R_i = 1 \text{ k}\Omega$,$I_C = 1 \text{ mA}$,and $I_b = 20 \text{ }\mu\text{A}$. The voltage gain is:

In a transistor,when the emitter current changes by $9.85 \,mA$,the collector current changes by $9.5 \,mA$. Then the base current is (in $\,mA$)

In a common base amplifier,the phase difference between the input and output voltage is .......

$A$ transistor is used in common-emitter mode in an amplifier circuit. When a signal of $10 \, mV$ is added to the base-emitter voltage, the base current changes by $10 \, \mu A$ and the collector current changes by $1.5 \, mA$. The load resistance is $5 \, k\Omega$. The voltage gain of the transistor will be

$Assertion$ : In common base configuration, the current gain of the transistor is less than unity.
$Reason$ : The collector terminal is reverse biased for amplification.

In the case of a transistor,what is the relationship between the current gain parameters $\alpha$ and $\beta$?