Suppose the thickness of the depletion layer | vedclass

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(C) Given:Thickness of the depletion layer,$d = 10^{-6} \ m$Depletion barrier potential,$V = 0.1 \ V$The relationship between the electric field $E$,p

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$10^5$

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(C) Given:Thickness of the depletion layer,$d = 10^{-6} \ m$Depletion barrier potential,$V = 0.1 \ V$The relationship between the electric field $E$,potential $V$,and distance $d$ is given by $V = E 	imes d$.Therefore,$E = \frac{V}{d}$.Substituting the values:$E = \frac{0.1}{10^{-6}} = 0.1 	imes 10^6 = 10^5 \ V \ m^{-1}$.Thus,the electric field is $10^5 \ V \ m^{-1}$.

Suppose the thickness of the depletion layer in a $P-N$ junction is $10^{-6} \ m$ and the value of the depletion barrier is $0.1 \ V$. Then the electric field is ....... $V \ m^{-1}$.

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