For a given transistor,if $\alpha = 0.95$,find the common emitter current gain $\beta$.

In an $n-p-n$ common emitter $(CE)$ transistor,the collector current changes from $5\,mA$ to $16\,mA$ for a change in base current from $100\,\mu A$ to $200\,\mu A$,respectively. The current gain of the transistor is:

In an $N-P-N$ transistor circuit,the common emitter configuration is used. $A$ load resistor $R_L$ is connected to the collector and a base resistor $R_B$ is connected to the base. Given $V_{CC} = 8V$,$V_{CE} = 4V$,$V_{BE} = 0.6V$,collector current $I_C = 4mA$,and current gain $\beta = 100$,find the values of $R_L$ and $R_B$ respectively.

In a common emitter amplifier circuit using an $n-p-n$ transistor,the phase difference between the input and the output voltages will be.....$^o$

If $ \alpha $-current gain of a transistor is $ 0.98 $,what is the value of $ \beta $-current gain of the transistor?

The region in the output voltage versus input voltage graph where a transistor can be used as an amplifier is