For the given circuit,what will be the truth | vedclass

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(C) The given circuit consists of a $NOR$ gate followed by a $NOT$ gate (represented by the second gate with shorted inputs). $1$. The output of the f

Vedclass · Accepted Answer

$A$$B$$Y$$0$$0$$0$$0$$1$$1$$1$$0$$1$$1$$1$$1$

Vedclass · Answer

(C) The given circuit consists of a $NOR$ gate followed by a $NOT$ gate (represented by the second gate with shorted inputs). $1$. The output of the first $NOR$ gate is $C = \overline{A+B}$. $2$. The second gate is a $NOT$ gate (since both inputs are connected together),so its output is $Y = \overline{C}$. $3$. Substituting $C$,we get $Y = \overline{(\overline{A+B})} = A+B$. $4$. This is the Boolean expression for an $OR$ gate. $5$. The truth table for an $OR$ gate is: - If $A=0, B=0$,then $Y=0$. - If $A=0, B=1$,then $Y=1$. - If $A=1, B=0$,then $Y=1$. - If $A=1, B=1$,then $Y=1$. This matches option $C$.

For the given circuit,what will be the truth table for the output $Y$ based on all possible inputs $A$ and $B$?

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