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(B) For an astronomical telescope in normal adjustment (distant vision),the final image is formed at infinity.The magnifying power $(M)$ is given by t

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(B) For an astronomical telescope in normal adjustment (distant vision),the final image is formed at infinity.The magnifying power $(M)$ is given by the formula:$M = -\frac{f_o}{f_e}$where $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eyepiece.Given:$f_o = 200 \, cm$$f_e = 4 \, cm$Substituting the values:$M = -\frac{200}{4} = -50$The magnitude of the magnifying power is $|M| = 50$.Therefore,the correct option is $B$.

If the focal lengths of the objective and eyepiece of an astronomical telescope are $200 \, cm$ and $4 \, cm$ respectively,what will be the magnifying power for distant vision (normal adjustment)?

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