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(C) The mirror formula is given by: $\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$Rearranging this equation to express $1/v$ in terms of $1/u$,we get:$\fra

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$C$

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(C) The mirror formula is given by: $\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$Rearranging this equation to express $1/v$ in terms of $1/u$,we get:$\frac{1}{v} = -\frac{1}{u} + \frac{1}{f}$This equation is of the form $y = mx + c$,where:$y = \frac{1}{v}$$x = \frac{1}{u}$$m = -1$ (slope is negative)$c = \frac{1}{f}$ (positive y-intercept)This represents a straight line with a negative slope and a positive y-intercept. Comparing this with the given options,graph $C$ represents a straight line with a negative slope and a positive intercept on the $1/v$ axis.

An object is placed at a distance $u$ from a concave mirror of focal length $f$. $A$ real image is formed on a screen placed at a distance $v$ from the mirror. As $u$ changes,$v$ also changes. Which of the following graphs correctly represents the variation of $1/v$ with $1/u$?

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