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(B) For $N$ identical cells in series,the total $EMF$ is $NE$ and total internal resistance is $Nr$. The current $I_s$ is given by $I_s = \frac{NE}{Nr

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$r = R$

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(B) For $N$ identical cells in series,the total $EMF$ is $NE$ and total internal resistance is $Nr$. The current $I_s$ is given by $I_s = \frac{NE}{Nr + R}$.For $N$ identical cells in parallel,the total $EMF$ is $E$ and total internal resistance is $r/N$. The current $I_p$ is given by $I_p = \frac{E}{r/N + R} = \frac{NE}{r + NR}$.Given that $I_s = I_p$,we have $\frac{NE}{Nr + R} = \frac{NE}{r + NR}$.This implies $Nr + R = r + NR$.Rearranging the terms: $Nr - r = NR - R$.$r(N - 1) = R(N - 1)$.Since $N 
eq 1$,we get $r = R$.

$N$ identical cells are connected in series or in parallel. When an external resistor $R$ is connected to them,they provide the same current. The internal resistance $r$ of each cell is:

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