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(A) The drift velocity is given by the formula $\upsilon_d = \frac{e	au V}{mL}$,where $e$ is the charge of an electron,$	au$ is the relaxation time,

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$1 : 2$

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(A) The drift velocity is given by the formula $\upsilon_d = \frac{e	au V}{mL}$,where $e$ is the charge of an electron,$	au$ is the relaxation time,$V$ is the potential difference,$m$ is the mass of the electron,and $L$ is the length of the conductor.Since the conductors are identical and kept at the same temperature,the relaxation time $	au$,mass $m$,and length $L$ are constant for both conductors.Therefore,the drift velocity is directly proportional to the potential difference: $\upsilon_d \propto V$.Thus,the ratio of the drift velocities is $\frac{\upsilon_{d1}}{\upsilon_{d2}} = \frac{V_1}{V_2}$.Given the ratio of potential differences is $1 : 2$,the ratio of drift velocities is $1 : 2$.

Two identical conductors are kept at the same temperature. If the ratio of the potential difference across them is $1 : 2$,what will be the ratio of their drift velocities?

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