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(B) From the circuit diagram,the resistor $R$ and the ammeter are in series,and this combination is in parallel with the voltmeter.However,the voltmet

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$100$

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(B) From the circuit diagram,the resistor $R$ and the ammeter are in series,and this combination is in parallel with the voltmeter.However,the voltmeter reading $V = 12\, 	ext{V}$ is the potential difference across the combination of $R$ and the ammeter.Using Ohm's law for the series combination of $R$ and the ammeter:$V = I(R + R_A)$Given $V = 12\, 	ext{V}$,$I = 0.1\, 	ext{A}$,and $R_A = 20\, \Omega$:$12 = 0.1(R + 20)$$12 / 0.1 = R + 20$$120 = R + 20$$R = 120 - 20 = 100\, \Omega$.

In the given circuit,the resistance of the voltmeter is $10,000\, \Omega$ and the resistance of the ammeter is $20\, \Omega$. The ammeter reading is $0.1\, \text{A}$. If the voltmeter reading is $12\, \text{V}$,then the value of $R$ is ............ $\Omega$.

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