(C) At $t = 0$,the capacitor acts as a short circuit (uncharged). The total resistance in the circuit is $1000\,\Omega$. Thus,the current $I = \frac{V

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At $t = 0$,$I = 2\,mA$ and as time passes,it becomes $1\,mA$

(C) At $t = 0$,the capacitor acts as a short circuit (uncharged). The total resistance in the circuit is $1000\,\Omega$. Thus,the current $I = \frac{V}{R} = \frac{2\,V}{1000\,\Omega} = 2\,mA$.As $t \to \infty$,the capacitor becomes fully charged and acts as an open circuit. The current now flows through the series combination of the two $1000\,\Omega$ resistors. The total resistance is $1000\,\Omega + 1000\,\Omega = 2000\,\Omega$. Thus,the current $I = \frac{V}{R_{total}} = \frac{2\,V}{2000\,\Omega} = 1\,mA$.

Class 12 Physics Electrostatic Potential and Capacitance Charging and Discharging of Capacitance and RC circuit (DC)

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When the switch $K$ is closed at $t = 0$,what can be said about the current passing through the resistor $AB$ in the given circuit?

A
For any $t$,$I = 2\,mA$
B
$I$ oscillates between $1\,mA$ and $2\,mA$
C
At $t = 0$,$I = 2\,mA$ and as time passes,it becomes $1\,mA$
D
At $t = 0$,$I = 1\,mA$ and as time passes,it becomes $2\,mA$

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Electrostatic Potential and Capacitance

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Charging and Discharging of Capacitance and RC circuit (DC)

What will be the current through the $200 \Omega$ resistor in the given circuit, a long time after the switch $K$ is closed?

MediumWBJEE 2018

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Given $R_1 = 1\,\Omega$,$C_1 = 2\,\mu F$ and $R_2 = 2\,\Omega$,$C_2 = 4\,\mu F$. The time constants (in $\mu s$) for the circuits $I, II, III$ are respectively:

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In the circuit shown,the switch is shifted from position $1 \rightarrow 2$ at $t = 0$. The switch was initially in position $1$ for a long time. The graph between the charge on capacitor $C$ and time $t$ is:

Medium

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In the circuit shown,the cells are ideal and of equal emfs $E$. The capacitance of the capacitor is $C$ and the resistance of the resistor is $R$. $X$ is first joined to $Y$ and then to $Z$. After a long time,the total heat produced in the resistor will be:

Medium

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$A$ capacitor $C = 100 \, \mu F$ is connected to three resistors,each of resistance $1 \, k\Omega$,and a battery of $emf$ $9 \, V$. The switch $S$ has been closed for a long time to charge the capacitor. When switch $S$ is opened,the capacitor discharges with a time constant of ...... $ms$.

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When the switch $K$ is closed at $t = 0$,what can be said about the current passing through the resistor $AB$ in the given circuit?

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What will be the current through the $200 \Omega$ resistor in the given circuit, a long time after the switch $K$ is closed?

Given $R_1 = 1\,\Omega$,$C_1 = 2\,\mu F$ and $R_2 = 2\,\Omega$,$C_2 = 4\,\mu F$. The time constants (in $\mu s$) for the circuits $I, II, III$ are respectively:

In the circuit shown,the switch is shifted from position $1 \rightarrow 2$ at $t = 0$. The switch was initially in position $1$ for a long time. The graph between the charge on capacitor $C$ and time $t$ is:

In the circuit shown,the cells are ideal and of equal emfs $E$. The capacitance of the capacitor is $C$ and the resistance of the resistor is $R$. $X$ is first joined to $Y$ and then to $Z$. After a long time,the total heat produced in the resistor will be:

$A$ capacitor $C = 100 \, \mu F$ is connected to three resistors,each of resistance $1 \, k\Omega$,and a battery of $emf$ $9 \, V$. The switch $S$ has been closed for a long time to charge the capacitor. When switch $S$ is opened,the capacitor discharges with a time constant of ...... $ms$.

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