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(C) Given: Current $I = 5\,A$, Resistance $R = 10\, \Omega$, Time $t = 4\, 	ext{minutes} = 4 	imes 60 = 240\,s$.First, calculate the total charge $Q

Vedclass · Accepted Answer

$75 	imes 10^{20}, 1200\ C$

Vedclass · Answer

(C) Given: Current $I = 5\,A$, Resistance $R = 10\, \Omega$, Time $t = 4\, 	ext{minutes} = 4 	imes 60 = 240\,s$.First, calculate the total charge $Q$ using the formula $Q = I 	imes t$:$Q = 5\,A 	imes 240\,s = 1200\,C$.Next, calculate the number of electrons $n$ using the quantization of charge formula $Q = n 	imes e$, where $e = 1.6 	imes 10^{-19}\,C$:$n = \frac{Q}{e} = \frac{1200}{1.6 	imes 10^{-19}} = \frac{12000}{1.6} 	imes 10^{18} = 7500 	imes 10^{18} = 75 	imes 10^{20}$.Thus, the number of electrons is $75 	imes 10^{20}$ and the charge is $1200\,C$.

$A$ current of $5\,A$ flows through a resistance of $10\, \Omega$ for $4$ minutes. The total charge in Coulombs and the number of electrons passing through any cross-section of the resistor in this time are, respectively:

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