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(C) In Young's double-slit experiment,the condition for constructive interference (maxima) is given by $d \sin 	heta = n \lambda$,where $d$ is the sl

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(C) In Young's double-slit experiment,the condition for constructive interference (maxima) is given by $d \sin 	heta = n \lambda$,where $d$ is the slit separation,$	heta$ is the angle,$n$ is the order of the maximum,and $\lambda$ is the wavelength.Given $d = 1.8 \lambda$,the condition becomes $1.8 \lambda \sin 	heta = n \lambda$,which simplifies to $1.8 \sin 	heta = n$.Since the maximum value of $\sin 	heta$ is $1$,the possible values for $n$ are limited by $|n| Thus,$n$ can take integer values $0, \pm 1$.For $n = 0$,we have the central maximum.For $n = 1$,we have the first-order maxima on both sides.For $n = -1$,we have the first-order maxima on both sides.Total number of maxima = $1 (n=0) + 2 (n=1) + 2 (n=-1) = 5$.

In Young's double-slit experiment,for a distance of $1.8 \lambda$ between the two slits,what is the maximum number of possible interference maxima? Here,$\lambda$ is the wavelength of light.

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