(A) The formula for the position of the $n^{th}$ bright fringe from the central maximum is given by $x_n = \frac{n \lambda D}{d}$.Given values:$n = 3$

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(A) The formula for the position of the $n^{th}$ bright fringe from the central maximum is given by $x_n = \frac{n \lambda D}{d}$.Given values:$n = 3$$\lambda = 6500 \, \mathring A = 6500 \times 10^{-10} \, m = 6.5 \times 10^{-7} \, m$$D = 120 \, cm = 1.2 \, m$$d = 2 \, mm = 2 \times 10^{-3} \, m$Substituting these values into the formula:$x_3 = \frac{3 \times 6.5 \times 10^{-7} \times 1.2}{2 \times 10^{-3}}$$x_3 = \frac{23.4 \times 10^{-7}}{2 \times 10^{-3}}$$x_3 = 11.7 \times 10^{-4} \, m$$x_3 = 1.17 \times 10^{-3} \, m = 0.117 \, cm$.Thus,the correct option is $A$.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

Medium

In a Young's double-slit experiment,light of two wavelengths $6500 \, \mathring A$ and $5200 \, \mathring A$ is used. Find the distance of the third bright fringe from the central maximum for the wavelength $6500 \, \mathring A$. The distance between the two slits is $2 \, mm$ and the distance between the plane of the slits and the screen is $120 \, cm$.

A
$0.117 \, cm$
B
$0.100 \, cm$
C
$0.90 \, cm$
D
None of the above

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Wave Optics

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Young's Double Slit Experiment (YDSE)

In a two-slit experiment with monochromatic light, fringes are obtained on a screen placed at some distance from the slits. If the screen is moved by $5 \times 10^{-2} \, m$ towards the slits, the change in fringe width is $3 \times 10^{-5} \, m$. If the separation between the slits is $10^{-3} \, m$, the wavelength of light used is: (in $\text{Å}$)

MediumKCET 2008

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Obtain the formula for the path difference at a point on the screen in Young's double-slit experiment in terms of $x$,$d$,and $D$.

Medium

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Consider a Young's double slit experiment as shown in the figure. What should be the slit separation $d$ in terms of wavelength $\lambda$ such that the first minima occurs directly in front of the slit $S_1$?

DifficultJEE MAIN 2019

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$A$ light of wavelength $500 \, nm$ is incident on a Young's double-slit. The distance between the slits and the screen is $D = 1.8 \, m$ and the distance between the slits is $d = 0.4 \, mm$. If the screen moves with a speed of $4 \, m/s$,with what speed will the first maxima move? (in $mm/s$)

DifficultAIIMS 2019

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White light is passed through a double slit and interference is observed on a screen $1.5 \, m$ away. The separation between the slits is $0.3 \, mm$. The first violet and red fringes are formed $2.0 \, mm$ and $3.5 \, mm$ away from the central white fringes. The difference in wavelengths of red and violet light is $.... \, nm$.

DifficultJEE MAIN 2021

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Obtain the formula for the path difference at a point on the screen in Young's double-slit experiment in terms of $x$,$d$,and $D$.

Consider a Young's double slit experiment as shown in the figure. What should be the slit separation $d$ in terms of wavelength $\lambda$ such that the first minima occurs directly in front of the slit $S_1$?

$A$ light of wavelength $500 \, nm$ is incident on a Young's double-slit. The distance between the slits and the screen is $D = 1.8 \, m$ and the distance between the slits is $d = 0.4 \, mm$. If the screen moves with a speed of $4 \, m/s$,with what speed will the first maxima move? (in $mm/s$)

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