In a double-slit interference experiment,if t | vedclass

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(C) The condition for destructive interference is given by the path difference $\Delta x = (2n - 1) \frac{\lambda}{2}$,where $n = 1, 2, 3, \dots$.Give

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dark

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(C) The condition for destructive interference is given by the path difference $\Delta x = (2n - 1) \frac{\lambda}{2}$,where $n = 1, 2, 3, \dots$.Given the path difference $\Delta x = \frac{3\lambda}{2}$,which corresponds to $n = 2$ in the destructive interference formula.Since the path difference is an odd multiple of $\lambda/2$,destructive interference occurs at this point.Therefore,the fringe at this point will be dark.

In a double-slit interference experiment,if the path difference at a point on the screen for yellow light is $3\lambda/2$,then the fringe at that point will be . . . . . .

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