(D) The fringe width $\beta$ is given by the formula $\beta = \frac{\lambda D}{d}$.Here,$\lambda$ is the wavelength of the monochromatic light,$D$ is

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The fringe width will remain unchanged.

(D) The fringe width $\beta$ is given by the formula $\beta = \frac{\lambda D}{d}$.Here,$\lambda$ is the wavelength of the monochromatic light,$D$ is the distance between the slits and the screen,and $d$ is the distance between the two slits.When a glass plate is introduced in the path of one of the beams,it introduces an additional path difference,which causes a shift in the entire interference pattern.However,the parameters $\lambda$,$D$,and $d$ remain unchanged.Therefore,the fringe width $\beta$ remains constant and does not change.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

Easy

In Young's double-slit experiment,monochromatic light is used to illuminate two slits $A$ and $B$. Interference fringes are obtained on a screen in front of the slits. Now,if a thick glass plate is placed in the path of light from one of the slits,then:

A
The fringes will disappear.
B
The fringe width will decrease.
C
The fringe width will increase.
D
The fringe width will remain unchanged.

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Wave Optics

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Young's Double Slit Experiment (YDSE)

In a Young's double-slit experiment, the angular width of a fringe is $1^\circ$ for light of wavelength $6000 \, \mathring{A}$. What is the distance between the slits in $mm$?

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In Young's double slit interference experiment,the slit separation is made $3$ fold. The fringe width becomes

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In a double-slit experiment performed in air, the angular width of a fringe is found to be $0.15^{\circ}$ on a screen placed $80 \ cm$ away. The wavelength of light used is $490 \ nm$. What is the angular width of the fringe if the entire apparatus is immersed in a medium of refractive index $\frac{5}{3}$ (in $^{\circ}$)?

MediumTS EAMCET 2022

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In a double-slit experiment, the angular width of a fringe for sodium light $(\lambda = 5890 \, \mathring{A})$ is $0.20^o$. If the fringe width increases by $10\%$, what is the change in the wavelength?

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In the ideal double-slit experiment,when a glass plate (refractive index $\mu = 1.5$) of thickness $t$ is introduced in the path of one of the interfering beams (wavelength $\lambda$),the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass plate is:

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In Young's double-slit experiment,monochromatic light is used to illuminate two slits $A$ and $B$. Interference fringes are obtained on a screen in front of the slits. Now,if a thick glass plate is placed in the path of light from one of the slits,then:

Similar Questions

In a Young's double-slit experiment, the angular width of a fringe is $1^\circ$ for light of wavelength $6000 \, \mathring{A}$. What is the distance between the slits in $mm$?

In Young's double slit interference experiment,the slit separation is made $3$ fold. The fringe width becomes

In a double-slit experiment, the angular width of a fringe for sodium light $(\lambda = 5890 \, \mathring{A})$ is $0.20^o$. If the fringe width increases by $10\%$, what is the change in the wavelength?

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