There are $(n + 1)$ white balls and $(n + 1)$ black balls. Each ball is numbered from $1$ to $(n + 1)$. In how many ways can these balls be arranged in a row such that no two balls of the same color are adjacent?

  • A
    $(2n + 2)!$
  • B
    $(2n + 2)! \times 2$
  • C
    $(n + 1)! \times 2$
  • D
    $2{(n + 1)!}^2$

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