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(C) The sample space $S = \{1, 2, 3, 4, 5, 6\}$,so $n(S) = 6$.Event $A$ is getting a number greater than $3$,so $A = \{4, 5, 6\}$ and $n(A) = 3$.Event

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(C) The sample space $S = \{1, 2, 3, 4, 5, 6\}$,so $n(S) = 6$.Event $A$ is getting a number greater than $3$,so $A = \{4, 5, 6\}$ and $n(A) = 3$.Event $B$ is getting a number less than $5$,so $B = \{1, 2, 3, 4\}$ and $n(B) = 4$.The intersection $A \cap B$ is the set of numbers that are both greater than $3$ and less than $5$,so $A \cap B = \{4\}$ and $n(A \cap B) = 1$.The union $A \cup B$ is the set of numbers that are either in $A$ or in $B$,so $A \cup B = \{1, 2, 3, 4, 5, 6\}$ and $n(A \cup B) = 6$.Therefore,$P(A \cup B) = \frac{n(A \cup B)}{n(S)} = \frac{6}{6} = 1$.

When a die is thrown,let event $A$ be getting a number greater than $3$,and let event $B$ be getting a number less than $5$. What is $P(A \cup B)$?

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