If the probabilities of a student passing in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let $P(A)$,$P(B)$,and $P(C)$ be the probabilities of passing in the first,second,and third grade respectively.Given $P(A) = 1/10$,$P(B) = 3/5$,and

Vedclass · Accepted Answer

$1/20$

Vedclass · Answer

(C) Let $P(A)$,$P(B)$,and $P(C)$ be the probabilities of passing in the first,second,and third grade respectively.Given $P(A) = 1/10$,$P(B) = 3/5$,and $P(C) = 1/4$.Since these events are mutually exclusive,the probability of passing in any of these grades is $P(A \cup B \cup C) = P(A) + P(B) + P(C)$.$P(A \cup B \cup C) = 1/10 + 3/5 + 1/4 = (2 + 12 + 5) / 20 = 19/20$.The probability of failing (getting a fourth grade) is $P(D) = 1 - P(A \cup B \cup C)$.$P(D) = 1 - 19/20 = 1/20$.Converting to decimal,$1/20 = 0.05 = 5/100 = 1/20$.

$P(A)$	$P(B)$	$P(A \cap B)$	$P(A \cup B)$
$\frac{1}{3}$	$\frac{1}{5}$	$\frac{1}{15}$	$........$

If the probabilities of a student passing in the first,second,or third grade are $1/10$,$3/5$,and $1/4$ respectively,then the probability of the student failing (getting a fourth grade) is ........

Similar Questions

If one card is drawn at random from a pack of $52$ cards,what is the probability that it is a king or a spade?

Let $A, B,$ and $C$ be events such that $P(A) = P(B) = P(C) = \frac{1}{4}, P(AB) = P(CB) = 0,$ and $P(AC) = \frac{1}{8}.$ Then $P(A \cup B) = \dots$

An event has odds in favour $4 : 5$. Then,the probability that the event occurs is:

If the probability of a horse $A$ winning a race is $1/4$ and the probability of a horse $B$ winning the same race is $1/5$,then the probability that either of them will win the race is (in $/20$)

Fill in the blanks in the following table:

$P(A)$ $P(B)$ $P(A \cap B)$ $P(A \cup B)$

$\frac{1}{3}$ $\frac{1}{5}$ $\frac{1}{15}$ $........$

Vedclass Test Series

Exam Paper Generator

Online Exam Module