If $6$ girls and $5$ boys are sitting in a row,what is the probability that no two boys sit together?

  • A
    $\frac{6! \times 7!}{11!}$
  • B
    $\frac{7! \times 5!}{11!}$
  • C
    $\frac{6! \times 7!}{2! \times 11!}$
  • D
    None of these

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