In a city,40% of the people have brown hair,2 | vedclass

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(B) Let $A$ be the event that a person has brown hair and $B$ be the event that a person has brown eyes. Given: $P(A) = \frac{40}{100} = 0.4$ $P(B) =

Vedclass · Accepted Answer

$3/8$

Vedclass · Answer

(B) Let $A$ be the event that a person has brown hair and $B$ be the event that a person has brown eyes. Given: $P(A) = \frac{40}{100} = 0.4$ $P(B) = \frac{25}{100} = 0.25$ $P(A \cap B) = \frac{15}{100} = 0.15$ We need to find the conditional probability $P(B|A)$,which is the probability that a person has brown eyes given that they have brown hair. Using the formula for conditional probability: $P(B|A) = \frac{P(A \cap B)}{P(A)}$ $P(B|A) = \frac{0.15}{0.40} = \frac{15}{40} = \frac{3}{8}$ Thus,the probability is $\frac{3}{8}$.

In a city,$40\%$ of the people have brown hair,$25\%$ have brown eyes,and $15\%$ have both brown hair and brown eyes. If a person is selected at random from those having brown hair,what is the probability that they also have brown eyes?

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