The median of $21$ observations is $40$. If each observation greater than the median is increased by $6$,what will be the new median of the observations?
- A$40$
- B$46$
- C$46 + \frac{40}{21}$
- D$46 - \frac{40}{21}$
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Similar Questions
The following data gives the distribution of height of students. The median of the distribution is:
Height (in $cm$) $160$ $150$ $152$ $161$ $156$ $154$ $155$ No of students $12$ $8$ $4$ $4$ $3$ $3$ $7$
| Height (in $cm$) | $160$ | $150$ | $152$ | $161$ | $156$ | $154$ | $155$ |
| No of students | $12$ | $8$ | $4$ | $4$ | $3$ | $3$ | $7$ |
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View SolutionThe mean and the median of the following ten numbers in increasing order $10, 22, 26, 29, 34, x, 42, 67, 70, y$ are $42$ and $35$ respectively. Then,$\frac{y}{x}$ is equal to:
DifficultJEE MAIN 2019
View SolutionFind the arithmetic mean of the following frequency distribution.
$x_i$ $5$ $8$ $11$ $14$ $17$ $f_i$ $4$ $5$ $6$ $10$ $20$
| $x_i$ | $5$ | $8$ | $11$ | $14$ | $17$ |
| $f_i$ | $4$ | $5$ | $6$ | $10$ | $20$ |
Medium
View SolutionCompute the median from the following table:
Marks obtained No. of students $0-10$ $2$ $10-20$ $18$ $20-30$ $30$ $30-40$ $45$ $40-50$ $35$ $50-60$ $20$ $60-70$ $6$ $70-80$ $3$
| Marks obtained | No. of students |
|---|---|
| $0-10$ | $2$ |
| $10-20$ | $18$ |
| $20-30$ | $30$ |
| $30-40$ | $45$ |
| $40-50$ | $35$ |
| $50-60$ | $20$ |
| $60-70$ | $6$ |
| $70-80$ | $3$ |
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View SolutionThe mean of a set of numbers is $\bar{x}$. If each number is multiplied by $\lambda$,then the mean of the new set is
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