Find the mode of the following frequency dist | vedclass

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(B) First,we convert the class intervals into continuous form by subtracting $0.5$ from the lower limit and adding $0.5$ to the upper limit.						Clas

Vedclass · Accepted Answer

$23.83$

Vedclass · Answer

(B) First,we convert the class intervals into continuous form by subtracting $0.5$ from the lower limit and adding $0.5$ to the upper limit.						Class			$0.5 - 10.5$			$10.5 - 20.5$			$20.5 - 30.5$			$30.5 - 40.5$			$40.5 - 50.5$							$f_i$			$5$			$7$			$8$			$6$			$4$			The modal class is $20.5 - 30.5$ as it has the highest frequency $f_1 = 8$.Here,$\ell = 20.5$,$f_1 = 8$,$f_0 = 7$,$f_2 = 6$,and $h = 10$.Mode $= \ell + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} ight) 	imes h$Mode $= 20.5 + \left( \frac{8 - 7}{2(8) - 7 - 6} ight) 	imes 10$Mode $= 20.5 + \left( \frac{1}{16 - 13} ight) 	imes 10$Mode $= 20.5 + \frac{10}{3} = 20.5 + 3.33 = 23.83$.

Find the mode of the following frequency distribution.

Class $1 - 10$ $11 - 20$ $21 - 30$ $31 - 40$ $41 - 50$

$f_i$ $5$ $7$ $8$ $6$ $4$

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Class	$1 - 10$	$11 - 20$	$21 - 30$	$31 - 40$	$41 - 50$
$f_i$	$5$	$7$	$8$	$6$	$4$

Find the mode of the following frequency distribution. Class $1 - 10$ $11 - 20$ $21 - 30$ $31 - 40$ $41 - 50$ $f_i$ $5$ $7$ $8$ $6$ $4$