The frequency distribution of the daily house | vedclass

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(D) The mode of the distribution is given as $140$. Since $140$ lies in the class interval $100-150$,the modal class is $100-150$.
The formula for mo

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$36$

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(D) The mode of the distribution is given as $140$. Since $140$ lies in the class interval $100-150$,the modal class is $100-150$.
The formula for mode is $Z = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} ight) 	imes h$.
Here,$l = 100$ (lower limit of modal class),$f_1 = 37$ (frequency of modal class),$f_0 = 33$ (frequency of preceding class),$f_2 = b$ (frequency of succeeding class),and $h = 50$ (class size).
Substituting the values:
$140 = 100 + \left( \frac{37 - 33}{2(37) - 33 - b} ight) 	imes 50$
$40 = \left( \frac{4}{74 - 33 - b} ight) 	imes 50$
$40 = \frac{200}{41 - b}$
$40(41 - b) = 200$
$41 - b = 5$
$b = 41 - 5 = 36$.
Thus,the value of $b$ is $36$.

Daily Expenditure (	$0-50$	$50-100$	$100-150$	$150-200$	$200-250$
Number of Families $(f)$	$24$	$33$	$37$	$b$	$25$

Daily wage (Rs.)	$30$-$40$	$40$-$50$	$50$-$60$	$60$-$70$	$70$-$80$	$80$-$90$
No. of workers	$17$	$28$	$21$	$15$	$13$	$6$

The frequency distribution of the daily household expenditure of some families in a residential area is given below. If the mode of the distribution is $140$,what is the value of $b$?

Daily Expenditure ( $0-50$ $50-100$ $100-150$ $150-200$ $200-250$

Number of Families $(f)$ $24$ $33$ $37$ $b$ $25$

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The frequency distribution of the daily household expenditure of some families in a residential area is given below. If the mode of the distribution is $140$,what is the value of $b$? Daily Expenditure ( $0-50$ $50-100$ $100-150$ $150-200$ $200-250$ Number of Families $(f)$ $24$ $33$ $37$ $b$ $25$