$A$ celestial object is observed from two points $A$ and $B$ on the Earth,which are diametrically opposite. The angle between the two observation directions is $2.9 \times 10^{-4} \text{ rad}$. Taking the diameter of the Earth to be $1.28 \times 10^4 \text{ km}$,find the distance between the Earth and the object.

  • A
    $2.268 \times 10^{-11} \text{ m}$
  • B
    $4.413 \times 10^7 \text{ m}$
  • C
    $4.413 \times 10^8 \text{ m}$
  • D
    $4.413 \times 10^{10} \text{ m}$

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