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(A) Given: Frequency $f = 880 \ kHz = 880 	imes 10^3 \ Hz$, Power $P = 10 \ kW = 10^4 \ J/s$.The energy of a single photon is given by $E_{photon} =

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$1.72 	imes 10^{31}$

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(A) Given: Frequency $f = 880 \ kHz = 880 	imes 10^3 \ Hz$, Power $P = 10 \ kW = 10^4 \ J/s$.The energy of a single photon is given by $E_{photon} = hf$, where $h = 6.626 	imes 10^{-34} \ J \cdot s$.Let $n$ be the number of photons emitted per second. The total power $P$ is equal to the energy emitted per second, so $P = n 	imes E_{photon} = n 	imes hf$.Rearranging for $n$: $n = \frac{P}{hf} = \frac{10^4}{(6.626 	imes 10^{-34}) 	imes (880 	imes 10^3)}$.$n = \frac{10^4}{5.83 	imes 10^{-28}} \approx 1.715 	imes 10^{31} \approx 1.72 	imes 10^{31}$ photons/second.

$A$ radio transmitter transmits at a frequency of $880 \ kHz$ and consumes $10 \ kW$ of power. The number of photons emitted per second from the transmitter is:

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