The energy of a photon with a wavelength of $6.20 \times 10^{-5} \ cm$ is ....... $eV$.

  • A
    $1$
  • B
    $0.01$
  • C
    $2$
  • D
    $0.02$

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The minimum intensity of light to be detected by the human eye is $10^{-10} \ W/m^2$. The number of photons of wavelength $5.6 \times 10^{-7} \ m$ entering the eye,with a pupil area of $10^{-6} \ m^2$,per second for vision will be nearly:

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$A$ parallel beam of light of wavelength $900 \, nm$ and intensity $100 \, W/m^2$ is incident on a surface perpendicular to the beam. The number of photons crossing $1 \, cm^2$ area perpendicular to the beam in one second is:

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