In Thomson's method for determining the e/m r | vedclass

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(B) In $J$.$J$. Thomson's experiment to determine the specific charge $(e/m)$ of an electron,the electron beam is subjected to both electric and magne

Vedclass · Accepted Answer

The electric field and magnetic field are perpendicular to each other and both are perpendicular to the electron beam.

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(B) In $J$.$J$. Thomson's experiment to determine the specific charge $(e/m)$ of an electron,the electron beam is subjected to both electric and magnetic fields.$1$. The electric field $(E)$ and the magnetic field $(B)$ are applied perpendicular to each other.$2$. Both the electric field $(E)$ and the magnetic field $(B)$ are applied perpendicular to the direction of the electron beam.$3$. By adjusting the fields such that the electron beam passes undeflected,the velocity of the electrons can be determined,and subsequently,the $e/m$ ratio is calculated.Therefore,the electric and magnetic fields are perpendicular to each other and both are perpendicular to the electron beam.

In Thomson's method for determining the $e/m$ ratio of an electron,which of the following conditions is true regarding the fields?

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