(B) According to Einstein's photoelectric equation,the maximum kinetic energy $K_{\max}$ is given by $K_{\max} = h\nu - h\nu_0$,where $\nu_0$ is the t

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(B) According to Einstein's photoelectric equation,the maximum kinetic energy $K_{\max}$ is given by $K_{\max} = h\nu - h\nu_0$,where $\nu_0$ is the threshold frequency.For frequency $\nu_1$,$K_1 = h(\nu_1 - \nu_0) \dots (i)$For frequency $\nu_2$,$K_2 = h(\nu_2 - \nu_0) \dots (ii)$Given the ratio $\frac{K_1}{K_2} = \frac{1}{k}$,we have:$\frac{h(\nu_1 - \nu_0)}{h(\nu_2 - \nu_0)} = \frac{1}{k}$$k(\nu_1 - \nu_0) = \nu_2 - \nu_0$$k\nu_1 - k\nu_0 = \nu_2 - \nu_0$$k\nu_1 - \nu_2 = k\nu_0 - \nu_0$$k\nu_1 - \nu_2 = \nu_0(k - 1)$$\nu_0 = \frac{k\nu_1 - \nu_2}{k - 1}$

Class 12 Physics Dual Nature of Radiation and matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

Medium

Photoelectrons are emitted from a metal surface for frequencies $\nu_1$ and $\nu_2$. If the ratio of the maximum kinetic energy of the emitted photoelectrons is $1 : k$,then the threshold frequency of the metal surface is:

A
$\frac{\nu_1 - \nu_2}{k - 1}$
B
$\frac{k\nu_1 - \nu_2}{k - 1}$
C
$\frac{k\nu_2 - \nu_1}{k - 1}$
D
$\frac{\nu_2 - \nu_1}{k}$

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Class 12 Questions

Class 12

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Chapter

Dual Nature of Radiation and matter

Subtopic

Einstein's Photoelectric Equation and Energy Quantum of Radiation

When the electromagnetic radiations of frequencies $4 \times 10^{15} \,Hz$ and $6 \times 10^{15} \,Hz$ fall on the same metal in different experiments,the ratio of maximum kinetic energy of electrons liberated is $1: 3$. The threshold frequency for the metal is ............... $\times 10^{15} Hz$.

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In a photoelectric experiment,light of energy $2.48 eV$ irradiates a photosensitive material. The stopping potential was measured to be $0.5 V$. The work function of the photosensitive material is: (in $eV$)

DifficultJEE MAIN 2024

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For a photoelectric cell,the graph showing the variation of stopping potential $(V_o)$ with frequency $(\nu)$ of incident light is best represented by:

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Initially,a photon of wavelength $\lambda_1$ falls on a photocathode and emits an electron of maximum energy $E_1$. If the wavelength of the incident photon is changed to $\lambda_2$,the maximum energy of the electron emitted becomes $E_2$. Then the value of $hc$ ($h=$ Planck's constant,$c=$ velocity of light) is

MediumTS EAMCET 2013

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Photoelectrons are emitted from a metal surface for frequencies $\nu_1$ and $\nu_2$. If the ratio of the maximum kinetic energy of the emitted photoelectrons is $1 : k$,then the threshold frequency of the metal surface is:

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When the electromagnetic radiations of frequencies $4 \times 10^{15} \,Hz$ and $6 \times 10^{15} \,Hz$ fall on the same metal in different experiments,the ratio of maximum kinetic energy of electrons liberated is $1: 3$. The threshold frequency for the metal is ............... $\times 10^{15} Hz$.

In a photoemissive cell with exciting wavelength $\lambda$,the fastest electron has speed $v$. If the exciting wavelength is changed to $\frac{3\lambda}{4}$,the speed of the fastest emitted electron will be

In a photoelectric experiment,light of energy $2.48 eV$ irradiates a photosensitive material. The stopping potential was measured to be $0.5 V$. The work function of the photosensitive material is: (in $eV$)

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