If the energy of a photon is E and its moment | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The energy of a photon is given by $E = h
u$,where $h$ is Planck's constant and $
u$ is the frequency.We know that the speed of light $c$ (or ve

Vedclass · Accepted Answer

$E/p$

Vedclass · Answer

(A) The energy of a photon is given by $E = h
u$,where $h$ is Planck's constant and $
u$ is the frequency.We know that the speed of light $c$ (or velocity of a photon $v$) is related to frequency and wavelength by $v = 
u\lambda$,so $
u = v/\lambda$.Substituting this into the energy equation: $E = h(v/\lambda) = (h/\lambda)v$.We are given the momentum of the photon as $p = h/\lambda$.Substituting $p$ into the energy equation: $E = pv$.Therefore,the velocity of the photon is $v = E/p$.

If the energy of a photon is $E$ and its momentum is $p$,given by the relations $E = h\nu$ and $p = h/\lambda$,what is the velocity of the photon?

Similar Questions

Which one of these is non-divisible?

If a photon has velocity $c$ and frequency $\nu$,then which of the following represents its wavelength?

In pair annihilation,an electron and a positron destroy each other to produce gamma radiation. How is the momentum conserved?

The energy of a photon is $E = h\nu$ and the momentum of a photon is $p = \frac{h}{\lambda}$. The velocity of the photon is:

$A$ transmitter of power $10 \text{ kW}$ emits radio waves of wavelength $500 \text{ m}$. The number of photons emitted per second by the transmitter is of the order of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module