The wavelength of a 1 keV photon is 1.24 tim | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The energy of a photon is given by $E = hf = \frac{hc}{\lambda}$.Given,$E_1 = 1 \ keV = 10^3 \ eV$ and $E_2 = 1 \ MeV = 10^6 \ eV$.The frequency $

Vedclass · Accepted Answer

$2.4 	imes 10^{20} \ Hz$

Vedclass · Answer

(B) The energy of a photon is given by $E = hf = \frac{hc}{\lambda}$.Given,$E_1 = 1 \ keV = 10^3 \ eV$ and $E_2 = 1 \ MeV = 10^6 \ eV$.The frequency $f$ is directly proportional to the energy $E$ $(f = E/h)$.Therefore,$\frac{f_2}{f_1} = \frac{E_2}{E_1} = \frac{10^6 \ eV}{10^3 \ eV} = 10^3$.First,find the frequency $f_1$ of the $1 \ keV$ photon:$f_1 = \frac{c}{\lambda_1} = \frac{3 	imes 10^8 \ m/s}{1.24 	imes 10^{-9} \ m} \approx 2.419 	imes 10^{17} \ Hz$.Now,calculate the frequency $f_2$ of the $1 \ MeV$ photon:$f_2 = f_1 	imes 10^3 = 2.419 	imes 10^{17} 	imes 10^3 \approx 2.4 	imes 10^{20} \ Hz$.

The wavelength of a $1 \ keV$ photon is $1.24 \times 10^{-9} \ m$. What is the frequency of a $1 \ MeV$ photon?

Similar Questions

Hydrogen behaves as an oxidising agent when it reacts with

$\int_0^{\pi / 2} \sin ^8 x \cos ^2 x \, dx$ is equal to

If $A+B=C$,then the value of $\cos^2 A + \cos^2 B + \cos^2 C - 2 \cos A \cos B \cos C$ is equal to

$A$ point moves in the $xy$-plane such that the sum of its distances from two mutually perpendicular lines is always equal to $5$ units. The area (in sq units) enclosed by the locus of the point is

For all real $x$,the minimum value of the function $f(x)=\frac{1-x+x^2}{1+x+x^2}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module