The ratio of the energy of X-rays with a wave | vedclass

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(B) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Since $h$ and $c$ are constants,the energy $E$ is inversely proportional t

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$5000 : 1$

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(B) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Since $h$ and $c$ are constants,the energy $E$ is inversely proportional to the wavelength $\lambda$,i.e.,$E \propto \frac{1}{\lambda}$.Therefore,the ratio of the energies is $\frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1}$.Given $\lambda_1 = 1 \ \mathring A$ and $\lambda_2 = 5000 \ \mathring A$.Substituting these values,we get $\frac{E_1}{E_2} = \frac{5000 \ \mathring A}{1 \ \mathring A} = 5000 : 1$.

The ratio of the energy of $X$-rays with a wavelength of $1 \ \mathring A$ to the energy of visible light with a wavelength of $5000 \ \mathring A$ is:

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